NokiMo
adorkabletwilightandfriends
adorkabletwilightandfriends

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If anyone has a good answer...

If anyone here has a good answer, we will use it.  The more math and science in your answer, the better the chances.  We got to make these seem like it was legit. Ha ha!  

If anyone has a good answer...

Comments

That would be far too easy. We need to make it complicated.

You sound like you actually know what you are talking about here. No joke, you seem like you are 100% serious in this answer!

I can imagine her in a valet vest eagerly waiting behind a little booth with her tail wagging.

You lost me at "multiplying by the amount of cookies." Clearly I am not educated enough to handle this kind of advanced arithmetic.

She does have a snort on occasion. Weird you brought that up because we have a future comic idea on that! It just hasn't been made yet!

The answer is deceptively simple; one can clearly observe how much Twilight's adorability has increased by being in a flower pot (even if the Heisenberg Uncertainty Principle guarantees that we cannot quantify the exact change, but rather only get within a factor of 2φ/π ( about 1.03)). Therefore by conservation of adorability all other adorable ponies must stay home today (unless they wear scary monster suits, of course), so sadly there can only be zero Lyras in the park.

Borg Lord

*draws picture of Lyra parking cars* (but no I can't really draw, so I guess you'll have to!)

kallenin

Albeit, if the twilight landed in the pot on a TUESDAY, the entire equation is just...just entirely botched.

Well you see, this is a loded question. Accounting for the number of pies pinkie has baked in the last 3 seconds, multiplying the color purple, varying for how small rainbow dash is even if she wont admit it, adding that to both the ammount of bon bons bon bon has nommed on, and the ammount of pixies trixy has fix-ied, then taking time to subtract the ammount of dances moon dancer has ACTUALLY done, taking that and multiplying it by a fraction of the times rarity said she didnt care over the times she ACTUALLY didnt care, carry the four, divide by the ammount of times weve judged spike for what he did that one time in the place with the thing (which is alot, you know what you did) multiply by the ammount of cookies starlight totally stole from the cookie jar, and finally, multiply by the amount that vinyl wubs us, and the grand total comes to... 'bout seven.

Yes, maybe... unless this particular Twily has the "Snorting Laugh" trait, then we would raise the dorkables by an additional 25 and then I think, if the math is corrects and the number of benches is unchanged I think we would have at least 17 absolute adorable Lyras plus a very confused Bon-Bon

Luis_El Oso_Graciano

Excuse me because I haven't used this level of math in a few weeks. ;-) I'm a bit rusty. I believe it comes in at 6,297 Lyra's. Check the 32nd row and you will see your error. ;-)

Hmmmm. *Scratches my chin* That seems plausible. Though I wonder if we were to divide that 100 adorbs by 50 dorkables. I think the outcome of Lyra's would certainly increase.

<a href="https://www.askamathematician.com/wp-content/uploads/2017/07/sml_small.jpg" rel="nofollow noopener" target="_blank">https://www.askamathematician.com/wp-content/uploads/2017/07/sml_small.jpg</a> This equation shows that there 6,295 Lyras in the park.

blaa6

Well, we have to factor the degree of Adrokableness of the Twilight, now according to the illustration this is a an Adorkable of high factor, so that would make for at least 100 adorbs, we factor this to the size of the flower pot, given the illustration this would be a Radious of 2 hooves, by a height of 4 hooves, apply QT- π algorithmic, multiply by the number of benches in the parks… aaand the result is one absolute adorable Lyra!

Luis_El Oso_Graciano


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